3x+10=x^2+16

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Solution for 3x+10=x^2+16 equation: 



3x+10=x^2+16

We move all terms to the left:

3x+10-(x^2+16)=0

We get rid of parentheses

-x^2+3x-16+10=0

We add all the numbers together, and all the variables

-1x^2+3x-6=0

a = -1; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-1)·(-6)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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